Toppers Study Toppers Study Toppers StudyGet CBSE Notes for Class 10 Science – 1. Chemical Reactions and Equations: Balancing A Chemical Equation. Clear, exam-focused notes with key concepts, formulas & solved examples.
CBSE Notes for Class 10 Science chapter 1. Chemical Reactions and Equations: Balancing A Chemical Equation, quick revision notes for Class 10 Science chapter 1. Chemical Reactions and Equations Balancing A Chemical Equation, Chapter-wise CBSE Revision Notes, CBSE Notes PDF Free Download, CBSE One Liner Notes Class 10, Half Yearly Revision Notes, CBSE Revision Notes Class 10 Science
Get CBSE Notes for Class 10 Science Chapter 1. Chemical Reactions and Equations: Balancing A Chemical Equation prepared by experts as per the latest NCERT syllabus and CBSE exam pattern. These concise and easy-to-understand notes cover important definitions, formulas, diagrams, and key concepts from the chapter to help students in quick revision and effective exam preparation. Whether you are studying for school tests, board exams, or competitive exams, these notes provide a reliable study resource. Designed in simple language with point-wise explanations, they save time and enhance learning efficiency. Download free PDF notes, explore solved examples, and strengthen your understanding of [Topic Name] for scoring high marks. Perfect for Class 10 students who want clear, structured, and exam-oriented notes for CBSE Science.
Here we would learn the method how to balance a chemical reaction.0
The method which we apply e.i hit and trail or inspecting method. Here we take Equation Fe + H2O → Fe3O4 + H2 as example I:
Steps;
(i) Write each formula in box or imagine that each formula is in box. It is so that you have to mind no changes should be made inside the box.
(ii) Count and list the numbers of atom of different element that present in unbalanced equation. Like this
Elements Reactant Product
Fe 1 3
O 1 4
H 2 2
First observe that what element has the maximum number of atoms. It may be from reactant and from product. Using this criteria we find that Fe3O4 is that compound and element is O that have maximum 4 atoms.
To equalise the number of atoms of oxygen, we can put the coefficient 4 with H2O as 4H2O. Then we get the equation as,
Fe + 4H2O → Fe3O4 + H2
(iii) The next maximum number of atoms having Fe. Which can be equalised
by same process.
Putting the coefficient 3 with Fe as 3Fe in reactant side. Now, the equation will be
3Fe + 4H2O → Fe3O4 + H2
(iv) Finally we come to equalise Hydrogen atom of both side. We observe that 4H2 in reactant and H2 in product. Total atom of hydrogen in reactant side is 4 × 2 = 8 and 2 in product. Then,
Here we cannot put 2 on LHS and 8 on RHS. (8 ÷ 2 ) =4 , the coefficient will be 4 that equalises hydrogen atom on RHS. So finally equation will be.
3Fe + 4H2O → Fe3O4 + 4H2 (balanced equation)
Example II. We take,
HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O
Steps:
(i) On observing the above chemical equation we see NO3 has maximum number of atoms/molecules. To equalise it we have on LHS 1 molecule and on RHS 2 molecules. So
Here Nitrogen and oxygen have been balanced, then Equation will be;
2HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O
(ii) Next calcium is already balanced, now we have to balance only hydrogen atoms.
Product need 2 as coefficient because (4 ÷ 2) = 2 , then equation will be;
2HNO3 + Ca (OH)2 → Ca(NO3)2 +2H2O
(iii) On counting and listing the numbers of atom of different element that present in equation above.
Elements Reactant Product
O 8 8
N 2 2
Ca 1 1
H 4 4
Hence we get a balanced equation
2HNO3 + Ca (OH)2 → Ca(NO3)2 +2H2O
I think now you have learnt how to balance a skeletal equation.
For students preparing for board exams or competitive assessments, CBSE notes have become an indispensable tool. These notes summarize the NCERT textbooks, highlighting key concepts, formulas, definitions, and diagrams in a concise and easy-to-understand format. Unlike lengthy textbooks, CBSE notes allow students to focus on the most important points, saving valuable time during revision.
In conclusion, CBSE notes are not just a revision tool—they are a strategy. When used correctly, they help students cover the syllabus efficiently, improve retention, and approach exams with confidence. For exam-going students, the combination of structured notes, practice, and consistent revision is the key to achieving top results.
Ace your exams with CBSE Notes for Class 10 Science chapter 1. Chemical Reactions and Equations: Balancing A Chemical Equation. These notes provide a clear explanation of important concepts, formulas, diagrams, and solved examples from the NCERT syllabus. Specially designed for Class 10 students, the notes are structured in a simple, point-wise manner to make revision quick and effective. Whether you are preparing for school tests, board exams, or competitive exams, these Science notes will boost your confidence and save valuable study time. You can also download Science class 10 chapter 1. Chemical Reactions and Equations free PDF notes for offline learning. With easy-to-grasp language, exam tips, and well-organized content, these CBSE Science notes on chapter 1. Chemical Reactions and Equations – Balancing A Chemical Equation are the perfect study companion for scoring high marks and mastering the subject.
CBSE class 10 Science notes are available completely free in PDF, and these all notes are quick revising materials that help you prepare for your upcoming board exams. Students can easily access CBSE notes pdf free download class 10 Science and get free CBSE notes class 10 Science notes designed strictly as per the latest NCERT syllabus. These Class 10 CBSE notes and Class 10 Science notes are short, simple, and to the point, making them perfect for last-minute revisions. You can also refer to NCERT book notes for class 10 that cover every chapter in an easy-to-understand manner. With these Quick revision notes Science class 10, you save time while covering all important formulas, definitions, and concepts.
Download worksheets and assignments for better practice and revision.