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CBSE NOTES Class 9 Mathematics Chapter-13. Surface Areas and Volumes page1



Explore Class 9 Mathematics Notes – 13. Surface Areas and Volumes: page1. Easy solutions, formulas, and step-by-step methods for exam preparation.

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CBSE NOTES Class 9 Mathematics Chapter-13. Surface Areas and Volumes page1

CBSE Notes for Class 9 Mathematics – chapter 13. Surface Areas and Volumes: page1 | Free PDF & Exam-Focused Study Material

Get CBSE Notes for Class 9 Mathematics Chapter 13. Surface Areas and Volumes: page1 prepared by experts as per the latest NCERT syllabus and CBSE exam pattern. These concise and easy-to-understand notes cover important definitions, formulas, diagrams, and key concepts from the chapter to help students in quick revision and effective exam preparation. Whether you are studying for school tests, board exams, or competitive exams, these notes provide a reliable study resource. Designed in simple language with point-wise explanations, they save time and enhance learning efficiency. Download free PDF notes, explore solved examples, and strengthen your understanding of [Topic Name] for scoring high marks. Perfect for Class 9 students who want clear, structured, and exam-oriented notes for CBSE Mathematics.

 

CBSE Notes ⇒ Class 9th ⇒ Mathematics

13. Surface Areas and Volumes

page1


Additional -Questions With Solutions

 

Q1. A cube and cuboid have same volume. The dimenstions of the cuboid are in the ratio 1 : 2: 4. if the difference between the cost of polishing the cube and cuboid at the rate of Rs. 5 per m2 is 80, find their volumes. 

Ans: 64 m3

Q2. The sum of length, breadth and depth of a cuboid is 19 cm and  the length of the diagonal in 11 cm. Find the surface area of the cuboid. 

                                   Ans: 240 cm2

Q3. The ratio of the curved surface area to the total surface area of a right circular cylinder is 1: 3. Find the volume of the cylinder if its total surface area is 1848 cm2

Ans: 4312 cm3

Q4. The cost of papering four walls of a room at Rs. 1.50 per square meter is Rs. 337.50. The height of the room is 5 m. Find the length and breadth of the room if they are in the ratio 4 : 1. 

Ans: l = 18 m, b= 4.5 

Q5. Circumference of the base of a cylinder open at top is 132 cm. The sum of radius and height of the cylinder 41 cm. FInd the cost of polishing the outer surface of cylinder at rate of Rs. 10 per square metre. 

Ans: Rs. 4.026 

Q6. The total surface area of a right circular cylinder is 6512 cm2, and the circumference of its base is 88 cm, find the volume of the cylinder. 

Ans: 36960 cm3 

Q7. The areas of three adjacent faces of a cuboid are 108 cm2, 72 cm2 and 96 cm2 respectively. Find the volume of the cuboid. Also find the dimensions of the cuboid. 

 Ans: Volume = 864 cm2, dimensions 12 cm x 9 cm x 8 cm 

Q8. A right circular cone is 5.4 cm high and radius of its base is 2 cm. It is melted and recast into another right circular cone with radius of base as 1.5 cm. Find the height of the new cone formed. 

Ans: 9.6 cm 

Q9. The radius  and height of a right circular cone are in the ratio 3 : 4. If its volume is 301.44 cm3, find its radius and slaint height. [take  π = 3.14]

Ans: Radius : 6 cm, height = 10 cm 

Q10. Four cubes each of side 5 cm are joined end to end. Find surface area of resultant cuboid. 

Ans: 450 cm2

Q11. A hemispherical dome of a building needs to be painted. If the circumference of the base of dome is 17.6 m, find the cost of painting it, at the rate of 5 per 100 cm2

Ans: Rs. 24640

Q12.  The difference between outsite and inside surfaces of cylinderical metallic pipe 14 cm ling is 44 cm2. If a pipe is made of 99 cm3 of metal, find the outer and inner radii of the pipe. 

Ans: R = 2.5 cm, r = 2 cm 

Q13. If in a sphere, volume  and surface area are numerically equal, find the radius. 

Ans: r = 3 units

Q14. Rain water which falls on a flat rectangular surface of length 6 m and breadth 4 m is transferred into a cylindrical vessel of internal radius 20 cm. What will be height of water in the cylinderical vessel if the rainfall is 1 cm ? Give naswer to the nearest whole number. [use  π = 3.14]

Ans: 192 cm

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