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Solutions 4. Determinants - Exercise 4.6 | Class 12 Mathematics-I - Toppers Study
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Solutions 4. Determinants - Exercise 4.6 | Class 12 Mathematics-I - Toppers Study
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Chapter 4 Mathematics-I class 12
Exercise 4.6 class 12 Mathematics-I Chapter 4. Determinants
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4. Determinants
| Exercise 4.6 |
Solutions 4. Determinants - Exercise 4.6 | Class 12 Mathematics-I - Toppers Study
Exercise - 4.6
Examine the consistency of the system of equations in Exercises 1 to 6.
Ques.1.
Ans. Matrix form of given equations is AX = B
A = and B =
=
There has Unique solution and hence equations are consistent.
Ques.2.
Ans. Matrix form of given equations is AX = B
A = and B =
=
There has Unique solution and hence equations are consistent.
Ques.3.
Ans. Matrix form of given equations is AX = B
A = and B =
= 6 – 6 = 0
Now (adj. A) B = =
Therefore, given equations are inconsistent, i.e., have no common solution.
Ques.4.
Ans. Matrix form of given equations is AX = B
A =
= 0
There has Unique solution and hence equations are consistent.
Ques.5.
Ans. Matrix form of given equations is AX = B
A =
= =
Now (adj. A) =
And (adj. A) B = = =
hance, given equations are inconsistent.
Ques.6.
Ans. Matrix form of given equations is AX = B
A =
=
There has Unique solution and hence equations are consistent.
Ques.7.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
so, solution is unique and =
=
hance, and
Ques.8.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
so, solution is unique and =
=
=
hance, and
Ques.9.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
so, solution is unique and =
=
=
hance, and
Ques.10.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
so, solution is unique and =
=
hance, and
Ques.11.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
= =
so, solution is unique and =
=
=
hance, and
Ques.12.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
=
so, solution is unique and =
=
=
hance, and
Ques.13.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
=
so, solution is unique and =
=
=
hance, and
Ques.14.
Ans. Matrix form of given equations is AX = B
A = , X = and B =
=
=
so, solution is unique and =
=
=
hance, and
Ques.15. If A = find Using solve the system of equations
Ans. Given: Matrix A =
=
……….(i)
Now, and and
adj. A = =
From eq. (i),
=
Now, Matrix form of given equations is AX = B
Here A = , X = and B =
so, solution is unique and
=
=
hance, and
Ques.16. The cost of 4 kg onion, 3 kg wheat and 2 kg rice is ` 60. The cost of 2 kg onion, 4 kg wheat and 2 kg rice is ` 90. The cost of 6 kg onion, 2 k wheat and 3 kg rice is ` 70. Find cost of each item per kg by matrix method.
Ans. Let ` ` ` per kg be the prices of onion, wheat and rice respectively.
According to given data, we have three equations,
Matrix form of given equations is AX = B
A = , X = and B =
= =
so, solution is unique and = …….(i)
Now,
adj. A =
From eq. (i),
=
=
so, and
Hence, the cost of onion, wheat and rice are 5, 8 and 8 per kg.
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