Our ncert solutions for Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

# Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

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## Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

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### You can Find Mathematics solution Class 11 Chapter 11. Conic Sections

- All Chapter review quick revision notes for chapter 11. Conic Sections Class 11
- NCERT Solutions And Textual questions Answers Class 11 Mathematics
- Extra NCERT Book questions Answers Class 11 Mathematics
- Importatnt key points with additional Assignment and questions bank solved.

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### Exercise 11.2 class 11 Mathematics Chapter 11. Conic Sections

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- Exercise 11.2 Class 11 Maths 11. Conic Sections - Ncert Solutions - Toppers Study
- Class 11 Ncert Solutions
- Solution Chapter 11. Conic Sections Class 11
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- Chapter 11. Conic Sections Exercise 11.2 Class 11

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## 11. Conic Sections

### | Exercise 11.2 |

## Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

## Exercise 11.2 (Conic Sections)

**Q1. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y ^{2} = 12x.**

**Solution:**

The given equation is y

^{2}= 12x.

Here, the coefficient of x is positive. Hence, the parabola opens towards the right.

On comparing this equation with y

^{2}= 4ax, we obtain

4a = 12 ⇒ a = 3

∴ Coordinates of the focus = (a, 0) = (3, 0)

Since the given equation involves y

^{2}, the axis of the parabola is the x-axis.

Equation of direcctrix, x = –a i.e., x = – 3 i.e., x + 3 = 0

Length of latus rectum = 4a = 4 × 3 = 12

**Q3. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y2 = – 8x.**

**Solution: **

The given equation is y^{2} = –8x.

Here, the coefficient of x is negative. Hence, the parabola opens towards the left.

On comparing this equation with y^{2} = –4ax, we obtain

–4a = –8 ⇒ a = 2

∴Coordinates of the focus = (–a, 0) = (–2, 0)

Since the given equation involves y^{2}, the axis of the parabola is the x-axis.

Equation of directrix, x = a i.e., x = 2

Length of latus rectum = 4a = 8

**Q4. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x ^{2} = – 16y.**

**Solution:**

The given equation is x

^{2}= –16y.

Here, the coefficient of y is negative. Hence, the parabola opens downwards.

On comparing this equation with x

^{2}= – 4ay, we obtain

–4a = –16 ⇒ a = 4

∴Coordinates of the focus = (0, –a) = (0, –4)

Since the given equation involves x

^{2}, the axis of the parabola is the y-axis.

Equation of directrix, y = a i.e., y = 4

Length of latus rectum = 4a = 16

**Q7. Find the equation of the parabola that satisfies the following conditions: Focus (6, 0); directrix x = –6.**

**Solution:**

Focus (6, 0); directrix, x = –6

Since the focus lies on the x-axis, the x-axis is the axis of the parabola.

Therefore, the equation of the parabola is either of the form y^{2} = 4ax or

y^{2} = – 4ax.

It is also seen that the directrix, x = – 6 is to the left of the y-axis, while the focus (6, 0) is to the right of the y-axis.

Hence, the parabola is of the form y^{2} = 4ax.

Here, a = 6

Thus, the equation of the parabola is y^{2} = 24x.

##### Other Pages of this Chapter: 11. Conic Sections

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